For a sewer with a 10 mg/L chlorine dosage and a flow rate of 0.37 mgd, what is the calculated feed rate?

For a sewer with a 10 mg/L chlorine dosage and a flow rate of 0.37 mgd, what is the calculated feed rate?

• A. 15.4 lb/day (7.0 kg/d)
• B. 30.8 lb/day (14 kg/d)
• C. 154 lb/day (70 kg/d)
• D. 308 lb/day (140 kg/d)

Answer: (B)

To calculate the feed rate of chlorine based on the given dosage and flow rate, you can use the following formula: \[ \text{Feed Rate (lb/day)} = \text{Dosage (mg/L)} \times \text{Flow Rate (mgd)} \times 8.34 \] Here, the dosage is given as 10 mg/L, and the flow rate is given as 0.37 mgd. To start, you multiply the dosage by the flow rate: \[ 10 \text{ mg/L} \times 0.37 \text{ mgd} = 3.7 \text{ mg/L} \cdot \text{mgd} \] Next, convert this to pounds per day using the conversion factor of 8.34: \[ 3.7 \text{ mg/L} \cdot 0.37 \text{ mgd} \cdot 8.34 \approx 30.8 \text{ lb/day} \] This calculation shows that the correct feed rate of chlorine for the given flow rate and dosage is indeed approximately 30.8 pounds per day, affirming the selection of that answer as correct. The importance of this

To calculate the feed rate of chlorine based on the given dosage and flow rate, you can use the following formula:

[ \text{Feed Rate (lb/day)} = \text{Dosage (mg/L)} \times \text{Flow Rate (mgd)} \times 8.34 ]

Here, the dosage is given as 10 mg/L, and the flow rate is given as 0.37 mgd.

To start, you multiply the dosage by the flow rate:

[ 10 \text{ mg/L} \times 0.37 \text{ mgd} = 3.7 \text{ mg/L} \cdot \text{mgd} ]

Next, convert this to pounds per day using the conversion factor of 8.34:

[ 3.7 \text{ mg/L} \cdot 0.37 \text{ mgd} \cdot 8.34 \approx 30.8 \text{ lb/day} ]

This calculation shows that the correct feed rate of chlorine for the given flow rate and dosage is indeed approximately 30.8 pounds per day, affirming the selection of that answer as correct.

The importance of this